$A$ capillary tube,when immersed vertically in a liquid,records a rise of $3 \, cm$. If the tube is immersed in the liquid at an angle of ${60^\circ}$ with the vertical,what is the length of the liquid column along the tube in $cm$?

It is not possible to write directly on blotting paper or newspaper with an ink pen.

If $M$ is the mass of water that rises in a capillary tube of radius $r,$ then the mass of water which will rise in a capillary tube of radius $2r$ is

Water rises to a height of $2.2 \text{ cm}$ in a glass capillary tube. The height to which the same water rises in another capillary having $\frac{1}{4}$ of the cross-sectional area is: (in $\text{ cm}$)

$A$ glass capillary of radius $0.35 \ mm$ is inclined at $60^{\circ}$ with the vertical in water. The length of the water column in the capillary is (surface tension of water $= 7 \times 10^{-2} \ N/m$,acceleration due to gravity $g = 10 \ m/s^2$,$\cos 0^{\circ} = 1$,$\cos 60^{\circ} = 0.5$,density of water $\rho = 10^3 \ kg/m^3$) (in $cm$)

Two vertical parallel plates are partially submerged in water. The distance between the plates is equal to $d$. Water rises due to surface tension $T$,the width of the plates is $l$,and the contact angle of water with glass is $0^o$. Find the force of attraction between the plates.