Judge the equivalent resistance when the foll | vedclass

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Question

(A) When two resistors $R_1$ and $R_2$ are connected in parallel,the equivalent resistance $R$ is given by the formula: $\frac{1}{R} = \frac{1}{R_1} +

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Less than $1\, \Omega$

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(A) When two resistors $R_1$ and $R_2$ are connected in parallel,the equivalent resistance $R$ is given by the formula: $\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}$.Given $R_1 = 1\, \Omega$ and $R_2 = 10^6\, \Omega$.Substituting the values: $\frac{1}{R} = \frac{1}{1} + \frac{1}{10^6} = 1 + 0.000001 = 1.000001\, \Omega^{-1}$.Therefore,$R = \frac{1}{1.000001} \approx 0.999999\, \Omega$.Since $0.999999\, \Omega < 1\, \Omega$,the equivalent resistance is slightly less than $1\, \Omega$.

Judge the equivalent resistance when the following are connected in parallel: $1\, \Omega$ and $10^6\, \Omega$.

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