Let a_1, a_2, a_3, dots, a_{100} be positive | vedclass

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(A) By Newton's Inequality or Maclaurin's Inequality,for positive real numbers $a_1, a_2, \dots, a_n$,let $e_k = \frac{S_k}{\binom{n}{k}}$.Then $e_k^2

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$\binom{100}{2}^2$

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(A) By Newton's Inequality or Maclaurin's Inequality,for positive real numbers $a_1, a_2, \dots, a_n$,let $e_k = \frac{S_k}{\binom{n}{k}}$.Then $e_k^2 \ge e_{k-1} e_{k+1}$.Specifically,for $n=100$,we have $S_k = \binom{n}{k} e_k$.Using the property $S_k S_{n-k} \ge \binom{n}{k}^2 (a_1 a_2 \dots a_n)$,we set $k=2$ and $n=100$.$S_2 S_{98} \ge \binom{100}{2}^2 (a_1 a_2 \dots a_{100})$.Here,$\binom{100}{2} = \frac{100 	imes 99}{2} = 4950$.Thus,$\lambda = \binom{100}{2}^2 = (4950)^2$.

Let $a_1, a_2, a_3, \dots, a_{100}$ be positive real numbers and $S_k$ be the sum of products of $a_1, a_2, \dots, a_{100}$ taken $k$ at a time. If $S_{98} S_2 \ge \lambda (a_1 a_2 \dots a_{100})$,then $\lambda$ is

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