Let A and B be two sets such that n(A)=3 and | vedclass

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(A) Given that $n(A) = 3$ and $n(B) = 2$. Since $(x, 1), (y, 2), (z, 1) \in A 	imes B$,the first elements of these ordered pairs must belong to set $

Vedclass · Accepted Answer

$A = \{x, y, z\}, B = \{1, 2\}$

Vedclass · Answer

(A) Given that $n(A) = 3$ and $n(B) = 2$. Since $(x, 1), (y, 2), (z, 1) \in A 	imes B$,the first elements of these ordered pairs must belong to set $A$ and the second elements must belong to set $B$. Thus,$A = \{x, y, z\}$ and $B = \{1, 2\}$. Since $n(A) = 3$ and $n(B) = 2$,these sets satisfy the given conditions. Therefore,$A = \{x, y, z\}$ and $B = \{1, 2\}$.

Let $A$ and $B$ be two sets such that $n(A)=3$ and $n(B)=2$. If $(x, 1), (y, 2), (z, 1)$ are in $A \times B$,find $A$ and $B$,where $x, y$ and $z$ are distinct elements.

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