Let $U$ be the universal set of all the students of Class $XI$ of a coeducational school and $A$ be the set of all girls in Class $XI$. Find $A'$.
(N/A) The universal set $U$ consists of all students in Class $XI$,which includes both boys and girls.
$A$ is the set of all girls in Class $XI$.
By definition,the complement of a set $A$,denoted by $A'$,is the set of all elements in $U$ that are not in $A$.
Therefore,$A' = U - A$ represents the set of all students in Class $XI$ who are not girls,which means $A'$ is the set of all boys in Class $XI$.
$A$ is the set of all girls in Class $XI$.
By definition,the complement of a set $A$,denoted by $A'$,is the set of all elements in $U$ that are not in $A$.
Therefore,$A' = U - A$ represents the set of all students in Class $XI$ who are not girls,which means $A'$ is the set of all boys in Class $XI$.
Explore More
Similar Questions
Taking the set of natural numbers as the universal set,write down the complement of the following set:
$A = \{ x : x \text{ is a prime number} \}$
$A = \{ x : x \text{ is a prime number} \}$
Easy
View SolutionIf $U = \{a, b, c, d, e, f, g, h\}$,find the complement of the set $B = \{d, e, f, g\}$.
Easy
View SolutionFor the two events $A$ and $B$,$P(A) = 0.38$ and $P(B) = 0.41$. Find the value of $P(\text{not } A)$.
Easy
View SolutionFill in the blanks to make each of the following a true statement:
$A \cap A^{\prime} = \ldots$
$A \cap A^{\prime} = \ldots$
Easy
View SolutionLet $U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}$,$A = \{1, 2, 5\}$,and $B = \{6, 7\}$. Find $A \cap B'$.
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo