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(C) The truth value of the implication $(p \wedge q) \rightarrow (\sim q \vee r)$ is $F$ (False).An implication $A \rightarrow B$ is false only when $

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$T, T, F$

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(C) The truth value of the implication $(p \wedge q) \rightarrow (\sim q \vee r)$ is $F$ (False).An implication $A \rightarrow B$ is false only when $A$ is $T$ (True) and $B$ is $F$ (False).Therefore,$(p \wedge q) = T$ and $(\sim q \vee r) = F$.For $(p \wedge q) = T$,both $p$ and $q$ must be $T$.Now,substitute $q = T$ into the second condition: $(\sim T \vee r) = F$.This simplifies to $(F \vee r) = F$.For this disjunction to be $F$,$r$ must be $F$.Thus,the truth values are $p = T, q = T, r = F$.

Let $p, q, r$ be three statements such that the truth value of $(p \wedge q) \rightarrow (\sim q \vee r)$ is $F$. Then the truth values of $p, q, r$ are respectively

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