(D) Let $f(a, b, c) = \frac{a^2+b^2+c^2}{ab+bc+ca}$.Case $1$: If $ab+bc+ca > 0$,we know that $(a-b)^2 + (b-c)^2 + (c-a)^2 \geq 0$,which implies $2(a^2

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$(-\infty, -2] \cup [1, \infty)$

(D) Let $f(a, b, c) = \frac{a^2+b^2+c^2}{ab+bc+ca}$.Case $1$: If $ab+bc+ca > 0$,we know that $(a-b)^2 + (b-c)^2 + (c-a)^2 \geq 0$,which implies $2(a^2+b^2+c^2) - 2(ab+bc+ca) \geq 0$,so $a^2+b^2+c^2 \geq ab+bc+ca$.Thus,$\frac{a^2+b^2+c^2}{ab+bc+ca} \geq 1$.Case $2$: If $ab+bc+ca This implies $a^2+b^2+c^2 \geq -2(ab+bc+ca)$.Since $ab+bc+ca $\frac{a^2+b^2+c^2}{ab+bc+ca} \leq -2$.Combining both cases,the range of $S$ is $(-\infty, -2] \cup [1, \infty)$.

Class 11 Mathematics 4-2.Quadratic Equations and Inequations Mix Examples-Quadratic Equations and Inequations

Let $S = \left\{ \frac{a^2+b^2+c^2}{ab+bc+ca} : a, b, c \in \mathbb{R}, ab+bc+ca \neq 0 \right\}$ where $\mathbb{R}$ is the set of real numbers. Then,$S$ equals

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A
$(-\infty, -1] \cup [1, \infty)$
B
$(-\infty, 0) \cup (0, \infty)$
C
$(-\infty, -1] \cup [2, \infty)$
D
$(-\infty, -2] \cup [1, \infty)$

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4-2.Quadratic Equations and Inequations

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Mix Examples-Quadratic Equations and Inequations

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DifficultJEE MAIN 2023

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MediumTS EAMCET 2023

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Let $S = \left\{ \frac{a^2+b^2+c^2}{ab+bc+ca} : a, b, c \in \mathbb{R}, ab+bc+ca \neq 0 \right\}$ where $\mathbb{R}$ is the set of real numbers. Then,$S$ equals

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If both roots of the quadratic equation $x^2 + (\sin \theta + \cos \theta)x + \frac{3}{8} = 0$ are positive and distinct,then the complete set of values of $\theta$ in $[0, 2\pi]$ is:

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