Let $9 < x_1 < x_2 < \ldots < x_7$ be in an $A.P.$ with common difference $d$. If the standard deviation of $x_1, x_2, \ldots, x_7$ is $4$ and the mean is $\overline{x}$,then $\overline{x} + x_6$ is equal to:

  • A
    $18\left(1+\frac{1}{\sqrt{3}}\right)$
  • B
    $34$
  • C
    $2\left(9+\frac{8}{\sqrt{7}}\right)$
  • D
    $25$

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