Let $A = \{\theta \in (0, 2\pi) : \frac{1+2i \sin \theta}{1-i \sin \theta} \text{ is purely imaginary} \}$. Then the sum of the elements in $A$ is

  • A
    $\pi$
  • B
    $2\pi$
  • C
    $4\pi$
  • D
    $3\pi$

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