Let a : sim (p wedge sim r) vee (sim q vee s) | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given $p = T, q = T, r = F, s = F$. For $a : \sim (p \wedge \sim r) \vee (\sim q \vee s)$: $a \equiv \sim (T \wedge \sim F) \vee (\sim T \vee F)$

Vedclass · Accepted Answer

$F, F$

Vedclass · Answer

(C) Given $p = T, q = T, r = F, s = F$. For $a : \sim (p \wedge \sim r) \vee (\sim q \vee s)$: $a \equiv \sim (T \wedge \sim F) \vee (\sim T \vee F)$ $a \equiv \sim (T \wedge T) \vee (F \vee F)$ $a \equiv \sim T \vee F$ $a \equiv F \vee F$ $a \equiv F$. For $b : (p \vee s) \leftrightarrow (q \wedge r)$: $b \equiv (T \vee F) \leftrightarrow (T \wedge F)$ $b \equiv T \leftrightarrow F$ $b \equiv F$. Thus,the truth values of $a$ and $b$ are $F$ and $F$ respectively.

Let $a : \sim (p \wedge \sim r) \vee (\sim q \vee s)$ and $b : (p \vee s) \leftrightarrow (q \wedge r)$. If the truth values of $p$ and $q$ are true and that of $r$ and $s$ are false,then the truth values of $a$ and $b$ are respectively:

Similar Questions

The dual of the converse of the inverse of the logical statement $p \to (q \to r)$ is equivalent to...

Negation of "Ram is in Class $X$ or Rashmi is in Class $XII$" is

The logical statement $(p \lor q) \land [(\sim p \land q) \lor (p \land \sim q)] \land \sim q$ is logically equivalent to ...

The statement $p \to (p \leftrightarrow q)$ is logically equivalent to :-

Check whether the following pair of statements are negation of each other. Give reasons for your answer.
$I$: There exists real numbers $x$ and $y$ for which $x+y=y+x.$
$II$: For all real numbers $x$ and $y$,$x+y \neq y+x.$

Vedclass Test Series

Exam Paper Generator

Online Exam Module