The statement p to (p leftrightarrow q) is lo | vedclass

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Question

(C) The truth table for $p 	o (p \leftrightarrow q)$ is as follows:$p$ | $q$ | $p \leftrightarrow q$ | $p 	o (p \leftrightarrow q)$$T$ | $T$ | $T$ |

Vedclass · Accepted Answer

$(q 	o p) 	o (p 	o q)$

Vedclass · Answer

(C) The truth table for $p 	o (p \leftrightarrow q)$ is as follows:$p$ | $q$ | $p \leftrightarrow q$ | $p 	o (p \leftrightarrow q)$$T$ | $T$ | $T$ | $T$$T$ | $F$ | $F$ | $F$$F$ | $T$ | $F$ | $T$$F$ | $F$ | $T$ | $T$Now,evaluating option $C$: $(q 	o p) 	o (p 	o q)$$p$ | $q$ | $q 	o p$ | $p 	o q$ | $(q 	o p) 	o (p 	o q)$$T$ | $T$ | $T$ | $T$ | $T$$T$ | $F$ | $T$ | $F$ | $F$$F$ | $T$ | $F$ | $T$ | $T$$F$ | $F$ | $T$ | $T$ | $T$Since the truth values match for all combinations of $p$ and $q$,the statement $p 	o (p \leftrightarrow q)$ is logically equivalent to $(q 	o p) 	o (p 	o q)$.

The statement $p \to (p \leftrightarrow q)$ is logically equivalent to :-

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