Let $f: R \rightarrow R$ be defined by $f(x)=3 x^2-5$ and $g: R \rightarrow R$ by $g(x)=\frac{x}{x^2+1}$,then $g \circ f$ is
- A$\frac{3 x^2-5}{9 x^4-6 x^2+26}$
- B$\frac{3 x^2}{x^4+2 x^2-4}$
- C$\frac{3 x^2}{9 x^4+30 x^2-2}$
- D$\frac{3 x^2-5}{9 x^4-30 x^2+26}$
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