Let $x$ denote the number of ways of arranging $m$ boys and $m$ girls in a row so that no two boys sit together. If $y$ and $z$ denote the number of ways of arranging $m$ boys and $m$ girls in a row and around a circular table respectively so that boys and girls sit alternately,then $x: y: z=$
- A$m+1: m: m-1$
- B$3: 2: 1$
- C$m-1: m: 2$
- D$(m+1)m: 2m: 1$
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