Let $f:(-1, 1) \to B$ be a function defined by $f(x) = \tan^{-1}\left(\frac{2x}{1-x^2}\right)$. Then $f$ is both one-one and onto when $B$ is the interval:
- A$[-\frac{\pi}{2}, \frac{\pi}{2}]$
- B$(-\frac{\pi}{2}, \frac{\pi}{2})$
- C$(0, \frac{\pi}{2})$
- D$[0, \frac{\pi}{2})$
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DifficultJEE MAIN 2026
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