Let $f(x) = \frac{\sqrt{x+3}}{x+1}$. Then the value of $\lim_{x \rightarrow -3^{-}} f(x)$ is

  • A
    $0$
  • B
    does not exist
  • C
    $\frac{1}{2}$
  • D
    $-\frac{1}{2}$

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