Let a, b, c be three real numbers such that a | vedclass

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(C) Given the equation $ax^2 + bx + c = 0$ and the condition $a + 2b + 4c = 0$. Divide the condition $a + 2b + 4c = 0$ by $4$: $\frac{a}{4} + \frac{2b

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has one of roots equal to $\frac{1}{2}$

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(C) Given the equation $ax^2 + bx + c = 0$ and the condition $a + 2b + 4c = 0$. Divide the condition $a + 2b + 4c = 0$ by $4$: $\frac{a}{4} + \frac{2b}{4} + \frac{4c}{4} = 0$ $\frac{a}{4} + \frac{b}{2} + c = 0$ This can be rewritten as: $a(\frac{1}{2})^2 + b(\frac{1}{2}) + c = 0$ Comparing this with the quadratic equation $f(x) = ax^2 + bx + c = 0$, we see that $f(\frac{1}{2}) = 0$. Therefore, $x = \frac{1}{2}$ is a root of the equation.

Let $a, b, c$ be three real numbers such that $a + 2b + 4c = 0$. Then the equation $ax^2 + bx + c = 0$

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