Let the locus of the point of intersection of the perpendicular tangents drawn to the circle $x^2+y^2+6x-4y-12=0$ be the circle $S$. Then the equation of the tangent drawn to $S$ which is perpendicular to the line $6x-4y+k=0$ is

  • A
    $4x+6y \pm \sqrt{26}=0$
  • B
    $2x+3y \pm \sqrt{26}=0$
  • C
    $2x+3y \pm 5\sqrt{26}=0$
  • D
    $4x+6y \pm 5\sqrt{26}=0$

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