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Question

(D) Work done per hour by machine $P = \frac{1}{8}$.Work done per hour by machine $Q = \frac{1}{10}$.Work done per hour by machine $R = \frac{1}{12}$.

Vedclass · Accepted Answer

$1.00$ p.m.

Vedclass · Answer

(D) Work done per hour by machine $P = \frac{1}{8}$.Work done per hour by machine $Q = \frac{1}{10}$.Work done per hour by machine $R = \frac{1}{12}$.All three machines work together from $9.00$ a.m. to $11.00$ a.m. ($2$ hours).Work done in $2$ hours $= 2 	imes (\frac{1}{8} + \frac{1}{10} + \frac{1}{12}) = 2 	imes (\frac{15+12+10}{120}) = 2 	imes \frac{37}{120} = \frac{37}{60}$.Remaining work $= 1 - \frac{37}{60} = \frac{23}{60}$.Machines $Q$ and $R$ work together to complete the remaining work in $x$ hours.Work done per hour by $Q$ and $R = \frac{1}{10} + \frac{1}{12} = \frac{6+5}{60} = \frac{11}{60}$.$x = \frac{23}{60} \div \frac{11}{60} = \frac{23}{11} = 2 \frac{1}{11}$ hours.$2 \frac{1}{11}$ hours is approximately $2$ hours and $5$ minutes.Starting from $11.00$ a.m.,adding $2$ hours and $5$ minutes gives $1.05$ p.m.,which is approximately $1.00$ p.m.

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