The major product of this reaction is:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction is a Prins reaction,which involves the electrophilic addition of an aldehyde (in this case,formaldehyde,$HCHO$) to an alkene in the p

Vedclass · Accepted Answer

$1-$methyl$-2-$(hydroxymethyl)cyclohexan$-1-$ol

Vedclass · Answer

(D) The reaction is a Prins reaction,which involves the electrophilic addition of an aldehyde (in this case,formaldehyde,$HCHO$) to an alkene in the presence of an acid catalyst $(H^+)$. $1$. The protonated formaldehyde acts as an electrophile and attacks the double bond of $1$-methylcyclohexene to form a carbocation intermediate. $2$. The carbocation is then attacked by water $(H_2O)$ to form the final product,which is $1$-methyl-$2$-(hydroxymethyl)cyclohexan-$1$-ol.

Similar Questions

Position of a double bond in an organic compound is determined by

$CH_3-CH=CH_2 + NOCl \rightarrow P$
Identify the adduct.

Ozonolysis of an organic compound gives formaldehyde as one of the products. This confirms the presence of:

Which of the following compounds reacts with $HBr$ to form $1$-Bromo-$1$-methylcyclohexane?

The compound $CH_3-C(CH_3)=CH-CH_3$ on reaction with $NaIO_4$ in the presence of $KMnO_4$ gives:

Vedclass Test Series

Exam Paper Generator

Online Exam Module