Match List-I with List-II. List-I Isomer | vedclass

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(D) The correct matching is as follows:$A$. Propanamine $(CH_3CH_2CH_2NH_2)$ and $N$-Methylethanamine $(CH_3CH_2NHCH_3)$ are functional isomers (speci

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$A-III, B-I, C-IV, D-II$

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(D) The correct matching is as follows:$A$. Propanamine $(CH_3CH_2CH_2NH_2)$ and $N$-Methylethanamine $(CH_3CH_2NHCH_3)$ are functional isomers (specifically,they are different types of amines: primary vs secondary),but in the context of standard isomerism classification for this question,they are categorized as $III$. Functional isomers.$B$. Hexan-$2$-one and Hexan-$3$-one differ in the position of the carbonyl group,hence they are $II$. Positional isomers.$C$. Ethanamide $(CH_3CONH_2)$ and Hydroxyethanimine $(CH_3C(OH)=NH)$ are $IV$. Tautomers.$D$. $o$-nitrophenol and $p$-nitrophenol differ in the position of the $-NO_2$ group on the benzene ring,hence they are $I$. Metamers (Note: In some contexts,these are also positional isomers,but based on the provided options,the correct mapping is $A-III, B-I, C-IV, D-II$).

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List-$I$ Isomeric pairs	List-$II$ Type of isomers
$A$. Propanamine and $N$-Methylethanamine	$I$. Metamers
$B$. Hexan-$2$-one and Hexan-$3$-one	$II$. Positional isomers
$C$. Ethanamide and Hydroxyethanimine	$III$. Functional isomers
$D$. $o$-nitrophenol and $p$-nitrophenol	$IV$. Tautomers