Match List-I with List-II. List-I (Coord | vedclass

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(B) The crystal field splitting energy $(\Delta)$ is inversely proportional to the wavelength of light absorbed $(\lambda_{abs})$,i.e.,$\Delta \propto

Vedclass · Accepted Answer

$A-III, B-II, C-I, D-IV$

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(B) The crystal field splitting energy $(\Delta)$ is inversely proportional to the wavelength of light absorbed $(\lambda_{abs})$,i.e.,$\Delta \propto \frac{1}{\lambda_{abs}}$.Stronger ligands cause larger splitting,resulting in the absorption of light with shorter wavelengths.The order of ligand field strength is: $CN^- > NH_3 > H_2O > Cl^-$.$1$. $[Co(CN)_6]^{3-}$: Strongest ligand $(CN^-)$,so it absorbs the shortest wavelength $(310 \ nm)$. $(C-I)$$2$. $[Co(NH_3)_6]^{3 }$: Strong ligand $(NH_3)$,absorbs $475 \ nm$. $(B-II)$$3$. $[CoCl(NH_3)_5]^{2 }$: Contains $Cl^-$ which reduces the overall field strength compared to $[Co(NH_3)_6]^{3 }$,absorbs $535 \ nm$. $(A-III)$$4$. $[Cu(H_2O)_4]^{2 }$: Weakest field among these,absorbs the longest wavelength $(600 \ nm)$. $(D-IV)$Therefore,the correct matching is $A-III, B-II, C-I, D-IV$.

List-$I$ (Coordination entity)	List-$II$ (Wavelength of light absorbed in $nm$)
$A$. $[CoCl(NH_3)_5]^{2+}$	$I$. $310$
$B$. $[Co(NH_3)_6]^{3+}$	$II$. $475$
$C$. $[Co(CN)_6]^{3-}$	$III$. $535$
$D$. $[Cu(H_2O)_4]^{2+}$	$IV$. $600$

List-$I$ (Electronic configuration of tetrahedral metal ion)	List-$II$ (Crystal Field Stabilization Energy $(\Delta_t)$)
$A$. $d^2$	$I$. $-0.6$
$B$. $d^4$	$II$. $-0.8$
$C$. $d^6$	$III$. $-1.2$
$D$. $d^8$	$IV$. $-0.4$

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Match the $LIST$-$I$ with $LIST$-$II$:

List-$I$ (Electronic configuration of tetrahedral metal ion) List-$II$ (Crystal Field Stabilization Energy $(\Delta_t)$)

$A$. $d^2$ $I$. $-0.6$

$B$. $d^4$ $II$. $-0.8$

$C$. $d^6$ $III$. $-1.2$

$D$. $d^8$ $IV$. $-0.4$

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