Match List-I with List-II: List-I | vedclass

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(B) The reactions of glucose are as follows:$1$. Glucose reacts with hydroxylamine $(NH_2OH)$ to form an oxime, known as Glucoxime $(A-IV)$.$2$. Gluco

Vedclass · Accepted Answer

$A-IV, B-I, C-II, D-III$

Vedclass · Answer

(B) The reactions of glucose are as follows:$1$. Glucose reacts with hydroxylamine $(NH_2OH)$ to form an oxime, known as Glucoxime $(A-IV)$.$2$. Glucose reacts with bromine water ($Br_2$ water) to undergo mild oxidation of the aldehyde group to a carboxylic acid, forming Gluconic acid $(B-I)$.$3$. Glucose reacts with excess acetic anhydride to form Glucose pentaacetate, indicating the presence of five hydroxyl groups $(C-II)$.$4$. Glucose reacts with concentrated nitric acid $(HNO_3)$ to undergo strong oxidation of both the aldehyde and the primary alcohol group, forming Saccharic acid $(D-III)$.Thus, the correct matching is $A-IV, B-I, C-II, D-III$.

List-$I$ (Reaction of glucose with)	List-$II$ (Product formed)
$A$. Hydroxylamine	$I$. Gluconic acid
$B$. $Br_2$ water	$II$. Glucose pentaacetate
$C$. Excess acetic anhydride	$III$. Saccharic acid
$D$. Concentrated $HNO_3$	$IV$. Glucoxime

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