Match the following reactions in Column-1 wit | vedclass

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(D) $1$. Diborane $(B_2H_6)$ is an electron-deficient species that acts as a Lewis acid. It reacts with carbon monoxide $(CO)$, a Lewis base, to form

Vedclass · Accepted Answer

$A-II, B-I, C-III$

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(D) $1$. Diborane $(B_2H_6)$ is an electron-deficient species that acts as a Lewis acid. It reacts with carbon monoxide $(CO)$, a Lewis base, to form a coordinate bond adduct:$B_2H_6 + 2CO \longrightarrow 2BH_3 \cdot CO$ $(A-II)$$2$. Diborane burns in oxygen to form boron trioxide $(B_2O_3)$:$B_2H_6 + 3O_2 \longrightarrow B_2O_3 + 3H_2O$ $(B-I)$$3$. Diborane undergoes hydrolysis with water to produce boric acid $(H_3BO_3)$:$B_2H_6 + 6H_2O \longrightarrow 2H_3BO_3 + 6H_2$ $(C-III)$Thus, the correct match is $A-II, B-I, C-III$.

Column-$1$ (Reaction)	Column-$2$ (Main product)
$A$. $B_2H_6 + 2CO \longrightarrow$	$I$. $B_2O_3$
$B$. $B_2H_6 + 3O_2 \longrightarrow$	$II$. $2BH_3 \cdot CO$
$C$. $B_2H_6 + 6H_2O \longrightarrow$	$III$. $2H_3BO_3$

Column-$I$	Column-$II$
$A$. $Bi^{+3} \to (BiO)^{+}$	$P$. Heat
$B$. $[AlO_2]^{-} \to Al(OH)_3$	$Q$. Hydrolysis
$C$. $SiO_4^{-4} \to Si_2O_7^{-6}$	$R$. Acidification
$D$. $(B_4O_7)^{-2} \to [B(OH)_3]$	$S$. Dilution with water

Similar Questions

Match Column-$I$ with Column-$II$ :

Column-$I$ Column-$II$

$A$. $Bi^{+3} \to (BiO)^{+}$ $P$. Heat

$B$. $[AlO_2]^{-} \to Al(OH)_3$ $Q$. Hydrolysis

$C$. $SiO_4^{-4} \to Si_2O_7^{-6}$ $R$. Acidification

$D$. $(B_4O_7)^{-2} \to [B(OH)_3]$ $S$. Dilution with water

Why is boric acid considered as a weak acid?

If the formula of Borax is $Na_2B_4O_x(OH)_y \cdot zH_2O$,then $x+y+z = ...........$.

The alloy formed from aluminum is ............ .

Aluminium $(III)$ chloride forms a dimer because aluminium

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