Match the following species in List-I with th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the number of lone pairs,we analyze the structure of each species:$A. \ CH_3COCH_3$ (Acetone): The oxygen atom has two lone pairs. So

Vedclass · Accepted Answer

$A-I, B-III, C-II$

Vedclass · Answer

(A) To determine the number of lone pairs,we analyze the structure of each species:$A. \ CH_3COCH_3$ (Acetone): The oxygen atom has two lone pairs. So,$A \rightarrow I$.$B. \ CH_3CO^+$ (Acylium ion): The oxygen atom is bonded to carbon by a triple bond $(CH_3-C \equiv O^+)$. The oxygen atom has one lone pair. So,$B \rightarrow III$.$C. \ CH_3CH_2^+$ (Ethyl carbocation): All valence electrons of carbon are involved in bonding (three $C-H$ bonds and one $C-C$ bond). There are no lone pairs on the carbocationic carbon. So,$C \rightarrow II$.Thus,the correct match is $A-I, B-III, C-II$.

List-$I$ (Species)	List-$II$ (Number of lone pairs)
$A. \ CH_3COCH_3$	$I. \ 2$
$B. \ CH_3CO^+$	$II. \ 0$
$C. \ CH_3CH_2^+$	$III. \ 1$
	$IV. \ 3$

Match the following species in List-$I$ with the number of lone pairs in List-$II$.
List-$I$ (Species) List-$II$ (Number of lone pairs)
$A. \ CH_3COCH_3$ $I. \ 2$
$B. \ CH_3CO^+$ $II. \ 0$
$C. \ CH_3CH_2^+$ $III. \ 1$
$IV. \ 3$

Similar Questions

The option$(s)$ in which at least three molecules follow the Octet Rule is(are):
$(A)$ $CO_2, C_2H_4, NO$ and $HCl$
$(B)$ $NO_2, O_3, HCl$ and $H_2SO_4$
$(C)$ $BCl_3, NO, NO_2$ and $H_2SO_4$
$(D)$ $CO_2, BCl_3, O_3$ and $C_2H_4$

If in $NH_3$ formation $N$ uses its pure atomic orbitals,then the wrong statement is:

Compare the $x$ and $y$ bond lengths in the following molecules:
Structure $1$: $HO-S(=O)-S(=O)-OH$ (where $x$ is the $S-S$ bond length)
Structure $2$: $HO-S(=O)_2-S(=O)-OH$ (where $y$ is the $S-S$ bond length)

Ionic and covalent bonds are present in

The formal charges of $N_{(1)}$,$N_{(2)}$ and $O$ atoms in the structure shown below are respectively:
$:N_{(1)}=N_{(2)}=\ddot{O}:$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Match the following species in List-$I$ with the number of lone pairs in List-$II$.List-$I$ (Species)List-$II$ (Number of lone pairs)$A. \ CH_3COCH_3$$I. \ 2$$B. \ CH_3CO^+$$II. \ 0$$C. \ CH_3CH_2^+$$III. \ 1$$IV. \ 3$