Match the following:

List-$I$	List-$II$
$a$. See-Saw Shape	$i$. $XeF_4$
$b$. Square Pyramidal	$ii$. $ClF_3$
$c$. $T$-Shape	$iii$. $PbCl_2$
$d$. Bent Shape	$iv$. $SF_4$
	$v$. $BrF_5$

The correct answer is

Assertion : $SeCl_4$ does not have a tetrahedral structure.
Reason : $Se$ in $SeCl_4$ has two lone pairs.

Which of the following compounds has the smallest bond angle $(X - A - X)$ in each series respectively?
$(A) \ OSF_2 \ \ \ \ \ \ \ \ \ OSCl_2 \ \ \ \ \ \ \ \ \ OSBr_2$
$(B) \ SbCl_3 \ \ \ \ \ \ \ \ \ SbBr_3 \ \ \ \ \ \ \ \ \ SbI_3$
$(C) \ PI_3 \ \ \ \ \ \ \ \ \ \ \ \ AsI_3 \ \ \ \ \ \ \ \ \ \ \ \ SbI_3$

$H_2O$ is

The increasing order of the number of lone pairs of electrons on the central atom of the following molecules is:
$I) \ ClF_3$
$II) \ XeF_2$
$III) \ SF_4$
$IV) \ SiH_4$

Among $CH_4$,$CO_2$,$H_2O$ and $SO_2$,the bond angle is the highest in