Match the species given in Column-$I$ with the properties mentioned in Column-$II$.

Column-$I$	Column-$II$
$A$. $BF_4^-$	$1$. Oxidation state of central atom is $+4$
$B$. $AlCl_3$	$2$. Strong oxidizing agent
$C$. $SnO$	$3$. Lewis acid
$D$. $PbO_2$	$4$. Can be further oxidized
	$5$. Tetrahedral shape

(A-5, B-3, C-4, D-1, 2) $A-5, B-3, C-4, D-1, 2$
$A$. In $BF_4^-$,$B$ is $sp^3$ hybridized,surrounded by $4$ bond pairs,and has no lone pair,resulting in a tetrahedral shape.
$B$. In $AlCl_3$,the octet of $Al$ is incomplete,making it an electron-deficient compound and a Lewis acid.
$C$. In $SnO$,the oxidation state of $Sn$ is $+2$,which can be further oxidized to $+4$.
$D$. In $PbO_2$,the oxidation state of $Pb$ is $+4$. Due to the inert pair effect,$Pb^{2+}$ is more stable than $Pb^{4+}$. Thus,$PbO_2$ acts as a strong oxidizing agent by reducing to $Pb^{2+}$.