What is the maximum number of moles of electr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The oxidation state of $N$ in $NO_3^-$ is $+5$. To find the number of moles of electrons taken up,we calculate the change in oxidation state for e

Vedclass · Accepted Answer

$NH_3$

Vedclass · Answer

(A) The oxidation state of $N$ in $NO_3^-$ is $+5$. To find the number of moles of electrons taken up,we calculate the change in oxidation state for each reduction product: $1$. For $NO_3^- \rightarrow NH_3$: Oxidation state of $N$ changes from $+5$ to $-3$. Electrons taken $= 5 - (-3) = 8 \ mol$. $2$. For $NO_3^- \rightarrow NH_2OH$: Oxidation state of $N$ changes from $+5$ to $-1$. Electrons taken $= 5 - (-1) = 6 \ mol$. $3$. For $NO_3^- \rightarrow NO$: Oxidation state of $N$ changes from $+5$ to $+2$. Electrons taken $= 5 - 2 = 3 \ mol$. $4$. For $NO_3^- \rightarrow NO_2$: Oxidation state of $N$ changes from $+5$ to $+4$. Electrons taken $= 5 - 4 = 1 \ mol$. The maximum number of moles of electrons taken up is $8 \ mol$ (when reduced to $NH_3$).

What is the maximum number of moles of electrons taken up by one mole of $NO_3^-$ when it is reduced to the given products?

Similar Questions

$A$ copper coin is completely covered with a gold film and is placed in dilute $HNO_3$. This will result in the formation of:

The autocatalyst in the redox reaction involving acidified potassium permanganate and oxalic acid is

The following reaction describes the rusting of iron:
$4Fe + 3O_2 \to 4Fe^{3+} + 6O^{2-}$
Which one of the following statements is incorrect?

The oxidation state of copper changes when aqueous copper $(II)$ ions react with
$(I)$ $NaOH_{(aq)}$
$(II)$ $Fe_{(s)}$
$(III)$ $KI_{(aq)}$

Which one of the following conversions does not involve either oxidation or reduction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module