The maximum value of sin x - cos x is equal t | vedclass

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(A) To find the maximum value of the expression $f(x) = \sin x - \cos x$,we can rewrite it in the form $R \sin(x - \alpha)$.We know that any expressio

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$\sqrt{2}$

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(A) To find the maximum value of the expression $f(x) = \sin x - \cos x$,we can rewrite it in the form $R \sin(x - \alpha)$.We know that any expression of the form $a \sin x + b \cos x$ has a range of $[-\sqrt{a^2 + b^2}, \sqrt{a^2 + b^2}]$.Here,$a = 1$ and $b = -1$.The maximum value is given by $\sqrt{a^2 + b^2} = \sqrt{1^2 + (-1)^2} = \sqrt{1 + 1} = \sqrt{2}$.Therefore,the maximum value is $\sqrt{2}$.

The maximum value of $\sin x - \cos x$ is equal to

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