Maximum value of the function $f(x) = [x(x-1) + 1]^{\frac{1}{3}}$ for $0 \leq x \leq 1$ is . . . . . . .

  • A
    $(\frac{1}{3})^{\frac{1}{3}}$
  • B
    $1$
  • C
    $\frac{1}{2}$
  • D
    $0$

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