Mercury is a liquid at $0 \, ^\circ C$ because of

  • A
    very high ionisation energy
  • B
    weak metallic bonds
  • C
    high heat of hydration
  • D
    Both $(a)$ and $(b)$

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Similar Questions

Given below are two statements:
Statement $I$: The number of pairs, from the following, in which both the ions are coloured in aqueous solution is $3$: $[Sc^{3+}, Ti^{3+}], [Mn^{2+}, Cr^{2+}], [Cu^{2+}, Zn^{2+}]$ and $[Ni^{2+}, Ti^{4+}]$.
Statement $II$: $Th^{4+}$ is the strongest reducing agent among $Th^{4+}, Ce^{4+}, Gd^{3+}$ and $Eu^{2+}$.
In the light of the above statements, choose the correct answer from the options given below:

Given below are two statements:
Statement $I$: Iron$(III)$ catalyst,acidified $K_{2}Cr_{2}O_{7}$ and neutral $KMnO_{4}$ have the ability to oxidise $I^{-}$ to $I_{2}$ independently.
Statement $II$: Manganate ion is paramagnetic in nature and involves $p\pi-p\pi$ bonding.
In the light of the above statements,choose the correct answer from the options.

Which of the following represents the correct order of stability for the given oxidation states?

Match the following properties with the corresponding metals:
Property Metal
$a$. Element with highest second ionization enthalpy $(\Delta_{i} H_2)$ $i$. $Co$
$b$. Element with highest third ionization enthalpy $(\Delta_{i} H_3)$ $ii$. $Cr$
$c$. $M$ in $[M(CO)_6]$ $iii$. $Cu$
$d$. Element with highest heat of atomization $(\Delta_{a} H)$ $iv$. $Zn$
$v$. $Ni$

Which of the following orders is correct?

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