Methyl alcohol can be distinguished from ethy | vedclass

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(C) The correct answer is $C$. Ethyl alcohol $(C_2H_5OH)$ contains a $CH_3CH(OH)-$ group,which gives a positive iodoform test with $NaOH$ and $I_2$,fo

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Sodium hydroxide and iodine

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(C) The correct answer is $C$. Ethyl alcohol $(C_2H_5OH)$ contains a $CH_3CH(OH)-$ group,which gives a positive iodoform test with $NaOH$ and $I_2$,forming a yellow precipitate of iodoform $(CHI_3)$. $C_2H_5OH + 4I_2 + 6NaOH \rightarrow CHI_3 + HCOONa + 5NaI + 5H_2O$. Methyl alcohol $(CH_3OH)$ does not contain this group and does not form a yellow precipitate with $NaOH$ and $I_2$.

Column-$I$ (Reactants)	Column-$II$ (Products)
$A$. $ROH + SOCl_2$	$i$. $RBr + NaHSO_4 + H_2O$
$B$. $ROH + PCl_5$	$ii$. $3RX + H_3PO_3$
$C$. $3ROH + PX_3$	$iii$. $RCl + SO_2 + HCl$
$D$. $ROH + NaBr + H_2SO_4$	$iv$. $RCl + POCl_3 + HCl$

Methyl alcohol can be distinguished from ethyl alcohol using

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