Molar conductivities $(\Lambda ^o_m)$ at infinite dilution of $NaCl$,$HCl$ and $CH_3COONa$ are $126.4$,$425.9$ and $91.0 \ S \ cm^2 \ mol^{-1}$ respectively. $(\Lambda ^o_m)$ for $CH_3COOH$ will be .......... $S \ cm^2 \ mol^{-1}$.
- A$425.5$
- B$180.5$
- C$290.8$
- D$390.5$
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The molar conductivities $\Lambda_{NaOH}^o$ and $\Lambda_{HCl}^o$ at infinite dilution in water at $25 ^\circ C$ are $91.0$ and $426.2 \ S \ cm^2/mol$ respectively. To calculate $\Lambda_{CH_3COOH}^o$,the additional value required is:
DifficultAIEEE 2006
View SolutionConductivity (unit $S$) is directly proportional to the area of the vessel $(A)$ and the concentration of the solution $(C)$ in it,and is inversely proportional to the length of the vessel $(l)$. The unit of the constant of proportionality is:
DifficultAIEEE 2002
View SolutionAt $25\,^{\circ}C$,the specific conductivity of a normal solution of $KCl$ is $0.002765\,S\,cm^{-1}$. The resistance of the cell is $400\,\Omega$. The cell constant is: (in $,cm^{-1}$)
Difficult
View SolutionThe specific conductivity of $N/10$ $KCl$ solution at $20\,^oC$ is $0.0212\,ohm^{-1}\,cm^{-1}$ and the resistance of the cell containing this solution at $20\,^oC$ is $55\,ohm$. The cell constant is ............. $cm^{-1}$.
MediumAIIMS 1999
View SolutionCalculate the cell constant of a conductivity cell containing $0.1 \ M$ $KCl$ solution having a resistance of $60 \ \Omega$ and a conductivity of $0.014 \ \Omega^{-1} \ cm^{-1}$ at $25^{\circ} \ C$. (in $cm^{-1}$)
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