The moment of inertia of a uniform circular disc about a diameter is $I$. What is its moment of inertia about an axis perpendicular to its plane and passing through a point on its rim (in $I$)?

$A$ solid sphere of radius $R$ and mass $M$ is rotating about its diameter. The moment of inertia of the solid sphere rotating about an axis at a distance $R/3$ from the centre and parallel to that diameter is

Two rings of the same radius and mass are placed such that their centers coincide and their planes are mutually perpendicular. The moment of inertia of the system about an axis passing through the center and perpendicular to the plane of one of the rings is ...... (where mass $= m$,radius $= r$)

The moment of inertia of a thin uniform rod of mass $M$ and length $L$ about an axis passing through its midpoint and perpendicular to its length is $I_0$. Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is

State and prove the theorem of perpendicular axes and the theorem of parallel axes.

$A$ uniform disc of radius $R$ lies in the $x-y$ plane with its centre at the origin. Its moment of inertia about the $z$-axis is equal to its moment of inertia about the line $y = x + c$. The value of $c$ is