(B) According to the theorem of parallel axes,the moment of inertia of a thin rod of mass $M$ and length $L$ about an axis passing through one of its

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(B) According to the theorem of parallel axes,the moment of inertia of a thin rod of mass $M$ and length $L$ about an axis passing through one of its ends is given by:$I = I_{CM} + Md^2$Where $I_{CM}$ is the moment of inertia of the rod about an axis passing through its center of mass (midpoint) and perpendicular to its length,and $d$ is the perpendicular distance between the two parallel axes.Here,$I_{CM} = I_0$ and the distance between the center and the end is $d = L/2$.Substituting these values into the theorem:$I = I_0 + M(L/2)^2$$I = I_0 + ML^2/4$

Class 11 Physics System of Particles and Rotational Motion Moment of Inertia of Compound Bodies and Theorem of Moment of Inertia

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The moment of inertia of a thin uniform rod of mass $M$ and length $L$ about an axis passing through its midpoint and perpendicular to its length is $I_0$. Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is

AIPMT 2011 All AIPMT

A
$I_0 + ML^2/2$
B
$I_0 + ML^2/4$
C
$I_0 + 2ML^2$
D
$I_0 + ML^2$

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System of Particles and Rotational Motion

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Moment of Inertia of Compound Bodies and Theorem of Moment of Inertia

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The moment of inertia of a thin uniform rod of mass $M$ and length $L$ about an axis passing through its midpoint and perpendicular to its length is $I_0$. Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is

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