(A) The electronic configuration of $Cerium$ ($Ce$,$Z=58$) is $[Xe] 4f^1 5d^1 6s^2$. Due to the loss of three electrons,it forms a stable $+3$ oxidati

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) The electronic configuration of $Cerium$ ($Ce$,$Z=58$) is $[Xe] 4f^1 5d^1 6s^2$. Due to the loss of three electrons,it forms a stable $+3$ oxidation state. It also exhibits a $+4$ oxidation state because the removal of four electrons results in a stable noble gas configuration $([Xe])$.