The number of unpaired electrons in the uranium $({ }_{92} U)$ atom is:
- A$4$
- B$6$
- C$3$
- D$1$
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Similar Questions
Match the properties given in List-$I$ with the elements given in List-$II$:
List-$I$ (Property) List-$II$ (Element) $(A)$ Lanthanoid showing $+4$ oxidation state $(i)$ $Pm$ $(B)$ Lanthanoid showing $+2$ oxidation state $(ii)$ $Ce$ $(C)$ Radioactive lanthanoid $(iii)$ $Lu$ $(D)$ Lanthanoid with $4f^7$ configuration in $+3$ state $(iv)$ $Eu$ $(E)$ Lanthanoid with $4f^{14}$ configuration in $+3$ state $(v)$ $Gd$ - $(vi)$ $Dy$
| List-$I$ (Property) | List-$II$ (Element) |
| $(A)$ Lanthanoid showing $+4$ oxidation state | $(i)$ $Pm$ |
| $(B)$ Lanthanoid showing $+2$ oxidation state | $(ii)$ $Ce$ |
| $(C)$ Radioactive lanthanoid | $(iii)$ $Lu$ |
| $(D)$ Lanthanoid with $4f^7$ configuration in $+3$ state | $(iv)$ $Eu$ |
| $(E)$ Lanthanoid with $4f^{14}$ configuration in $+3$ state | $(v)$ $Gd$ |
| - | $(vi)$ $Dy$ |
Medium
View SolutionWhich is the general formula for the electronic configuration of the actinide series?
Cerium $(Z = 58)$ is an important member of the lanthanoids. Which of the following statements about cerium is incorrect?
DifficultAIEEE 2004
View SolutionWhich of the following elements are included in the actinoid series?
Easy
View SolutionLarger number of oxidation states are exhibited by the actinoids than those by the lanthanoids,the main reason being
Medium
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