The net magnetic field at the centre $O$ of the circle due to the current-carrying loop as shown in the figure is $(\theta < 180^\circ)$.

  • A
    zero
  • B
    perpendicular to paper inwards
  • C
    perpendicular to paper outwards
  • D
    is perpendicular to paper inwards if $\theta \le 90^\circ$ and perpendicular to paper outwards if $90^\circ \le \theta < 180^\circ$

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