Nitin borrowed some money at the rate of 6 % | vedclass

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(C) Let the principal amount borrowed be $₹ x$.The total interest is calculated based on the simple interest formula: $SI = \frac{P 	imes R 	imes T}

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$8000$

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(C) Let the principal amount borrowed be $₹ x$.The total interest is calculated based on the simple interest formula: $SI = \frac{P 	imes R 	imes T}{100}$.For the first $3$ years at $6 \% 	ext{ p.a.}$,interest $= \frac{x 	imes 6 	imes 3}{100} = \frac{18x}{100}$.For the next $5$ years at $9 \% 	ext{ p.a.}$,interest $= \frac{x 	imes 9 	imes 5}{100} = \frac{45x}{100}$.For the remaining period of $11 - (3 + 5) = 3$ years at $13 \% 	ext{ p.a.}$,interest $= \frac{x 	imes 13 	imes 3}{100} = \frac{39x}{100}$.The total interest is given as $₹ 8,160$.Therefore,$\frac{18x + 45x + 39x}{100} = 8160$.$\frac{102x}{100} = 8160$.$102x = 816000$.$x = \frac{816000}{102} = 8000$.Thus,the money borrowed by Nitin was ₹ $8,000$.

Nitin borrowed some money at the rate of $6 \% \text{ p.a.}$ for the first three years,$9 \% \text{ p.a.}$ for the next five years,and $13 \% \text{ p.a.}$ for the period beyond eight years. If the total interest paid by him at the end of eleven years is ₹ $8,160$,the money borrowed by him was:

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