Nitrobenzene on nitration gives

  • A
    $o-$dinitrobenzene
  • B
    $p-$dinitrobenzene
  • C
    $m-$dinitrobenzene
  • D
    $o-$ and $p-$dinitrobenzene

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The decreasing order of reactivity of the given compounds towards nucleophilic substitution with aqueous $NaOH$ is:
$(I)$ $1$-bromo-$3$-nitrobenzene
$(II)$ $1$-bromo-$2,4,6$-trinitrobenzene
$(III)$ $1$-bromo-$4$-nitrobenzene
$(IV)$ $1$-bromo-$2,4$-dinitrobenzene

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