Nitrobenzene on reduction using zinc in alkal | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reduction of nitrobenzene with zinc in an alkaline medium (e.g.,$Zn/NaOH$) yields hydrazobenzene $(C_{12}H_{12}N_2)$ as the product $X$.Struct

Vedclass · Accepted Answer

$27 \sigma, 6 \pi$

Vedclass · Answer

(D) The reduction of nitrobenzene with zinc in an alkaline medium (e.g.,$Zn/NaOH$) yields hydrazobenzene $(C_{12}H_{12}N_2)$ as the product $X$.Structure of hydrazobenzene: $C_6H_5-NH-NH-C_6H_5$.Calculation of bonds:$1$. Each phenyl ring $(C_6H_5)$ contains $6$ $C-C$ bonds (including $3$ $\pi$ bonds),$5$ $C-H$ bonds,and $1$ $C-N$ bond.$2$. Total $\sigma$ bonds = $(6 	imes 2) + (5 	imes 2) + (1 	imes 2) + (N-N \sigma) + (2 	imes N-H \sigma) = 12 + 10 + 2 + 1 + 2 = 27$.$3$. Total $\pi$ bonds = $3$ (in first ring) + $3$ (in second ring) = $6$.Thus,$X$ contains $27 \sigma$ and $6 \pi$ bonds.

Nitrobenzene on reduction using zinc in alkaline medium results in $X$. The number of $\sigma$ and $\pi$ bonds in $X$ is

Similar Questions

$A$ body thrown vertically upwards from the ground reaches a maximum height $h$. The ratio of the kinetic and potential energies of the body at a height $40 \%$ of $h$ from the ground is

$\mathop {\lim}\limits_{x \to 0} \frac{{\sin \left( {\pi {{\cos }^2}x} \right)}}{{{x^2}}} = $

Which one of the following is a secondary alcohol?

If $X$ is a Poisson variate such that $P(X=1)=2 P(X=2)$, then $P(X=3)$ is equal to

The monomers of $Buna-S$ rubber are

Vedclass Test Series

Exam Paper Generator

Online Exam Module