(D) The structure of vinyl acetylene is $CH_2=CH-C \equiv CH$.In this molecule:- The two $sp^2$ hybridized carbon atoms each have $1$ unhybridised $p$

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) The structure of vinyl acetylene is $CH_2=CH-C \equiv CH$.In this molecule:- The two $sp^2$ hybridized carbon atoms each have $1$ unhybridised $p$-orbital.- The two $sp$ hybridized carbon atoms each have $2$ unhybridised $p$-orbitals.Total unhybridised $p$-orbitals $= (2 \times 1) + (2 \times 2) = 2 + 4 = 6$.

Class 11 Chemistry Chemical Bonding and Molecular Structure Hybridisation

Medium

Number of unhybridised orbitals in vinyl acetylene is

A
$2$
B
$3$
C
$4$
D
$6$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

Chemical Bonding and Molecular Structure

Subtopic

Hybridisation

The molecule of $CO_2$ has a $180^{\circ}$ bond angle. It can be explained on the basis of:

Medium

View Solution

$X$ and $Y$ are two covalent molecules in which the hybridization of the central atoms is the same,but their shapes are different. $X$ and $Y$ are:

MediumAP EAMCET 2018

View Solution

Which one of the following statements is true for the ammonium ion $(NH_4^+)$?

Medium

View Solution

Which set of hybridisation is correct for the following compounds:
$NO_2$,$SF_4$,$PF_6^-$

Medium

View Solution

As the $s-$character of a hybridized orbital decreases,the bond angle

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Number of unhybridised orbitals in vinyl acetylene is

Similar Questions

The molecule of $CO_2$ has a $180^{\circ}$ bond angle. It can be explained on the basis of:

$X$ and $Y$ are two covalent molecules in which the hybridization of the central atoms is the same,but their shapes are different. $X$ and $Y$ are:

Which one of the following statements is true for the ammonium ion $(NH_4^+)$?

Which set of hybridisation is correct for the following compounds:$NO_2$,$SF_4$,$PF_6^-$

As the $s-$character of a hybridized orbital decreases,the bond angle

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Which set of hybridisation is correct for the following compounds:
$NO_2$,$SF_4$,$PF_6^-$