The molecule of $CO_2$ has a $180^{\circ}$ bond angle. It can be explained on the basis of:

  • A
    $sp^3$ hybridisation
  • B
    $sp^2$ hybridisation
  • C
    $sp$ hybridisation
  • D
    $d^2sp^3$ hybridisation

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In $CO_2$,$C$ is $sp$ hybridised using $s$ and $p_x$ orbitals. Then:

Which of the underlined atoms in the molecules shown below have $sp$-hybridization?
$(u) H_2\underline{C}=CH-CH_3$
$(v) CH_2=\underline{C}=CHCl$
$(w) CH_3-\underline{C}H_2^+$
$(x) H-C \equiv C-H$
$(y) CH_3-\underline{C} \equiv N$
$(z) (CH_3)_2C=\underline{N}-NH_2$

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