Observe the following data given in the table $(K_H = \text{Henry's law constant})$. The correct order of solubility of these gases is:
Gas $K_H$ (kbar at $298 \ K$) $CO_2$ $1.67$ $Ar$ $40.3$ $HCHO$ $1.83 \times 10^{-5}$ $CH_4$ $0.413$
| Gas | $K_H$ (kbar at $298 \ K$) |
| $CO_2$ | $1.67$ |
| $Ar$ | $40.3$ |
| $HCHO$ | $1.83 \times 10^{-5}$ |
| $CH_4$ | $0.413$ |
- A$CO_2 > CH_4 > HCHO > Ar$
- B$Ar > HCHO > CH_4 > CO_2$
- C$HCHO > CH_4 > CO_2 > Ar$
- D$CO_2 > HCHO > CH_4 > Ar$
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