Observe the following reaction: $I_2 + 10 HNO_3 \rightarrow 2 HIO_3 + 10 NO_2 + 4 H_2O$. The equivalent weight of $HNO_3$ is (molar mass of $HNO_3 = M$).

  • A
    $M$
  • B
    $\frac{M}{4}$
  • C
    $\frac{M}{2}$
  • D
    $\frac{M}{5}$

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