Observe the following reaction:
xS_{8text{(s | vedclass

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Question

(A) The given reaction is a disproportionation reaction of sulfur $(S_8)$.
To balance the reaction $xS_8 + yOH^- \rightarrow zS^{2-} + 2S_2O_3^{2-} +

Vedclass · Accepted Answer

$1, 12, 4$

Vedclass · Answer

(A) The given reaction is a disproportionation reaction of sulfur $(S_8)$.
To balance the reaction $xS_8 + yOH^- ightarrow zS^{2-} + 2S_2O_3^{2-} + 6H_2O$:
Step $1$: Balance sulfur atoms. There are $8$ sulfur atoms on the left. On the right,there are $z$ atoms in $S^{2-}$ and $2 	imes 2 = 4$ atoms in $2S_2O_3^{2-}$. Thus,$z + 4 = 8$,which gives $z = 4$.
Step $2$: Balance oxygen atoms. There are $y$ oxygen atoms on the left. On the right,there are $2 	imes 3 = 6$ atoms in $2S_2O_3^{2-}$ and $6$ atoms in $6H_2O$. Thus,$y = 6 + 6 = 12$.
Step $3$: Balance hydrogen atoms. There are $y$ hydrogen atoms on the left and $6 	imes 2 = 12$ on the right. This confirms $y = 12$.
Step $4$: The coefficient $x$ for $S_8$ is $1$ to satisfy the sulfur balance.
Therefore,$x = 1, y = 12, z = 4$.

Observe the following reaction:
$xS_{8\text{(s)}} + yOH^{-}{_{\text{(aq)}}} \rightarrow zS^{2-}{_{\text{(aq)}}} + 2S_2O_3^{2-}{_{\text{(aq)}}} + 6H_2O_{\text{(l)}}$
Find the values of $x, y$ and $z$ respectively.

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Observe the following reaction: $xS_{8\text{(s)}} + yOH^{-}{_{\text{(aq)}}} \rightarrow zS^{2-}{_{\text{(aq)}}} + 2S_2O_3^{2-}{_{\text{(aq)}}} + 6H_2O_{\text{(l)}}$ Find the values of $x, y$ and $z$ respectively.