Obtain a pair of linear equations in two variables from the following information: Three years ago,the age of Abhishek was four times the age of Sweta. After five years,the age of Abhishek will be two times the age of Sweta.

(N/A) Let the present age of Abhishek be $x$ years and the present age of Sweta be $y$ years.
Case $1$: Three years ago,Abhishek's age was $(x-3)$ and Sweta's age was $(y-3)$.
According to the problem: $(x-3) = 4(y-3)$
$x-3 = 4y-12$
$x-4y = -9$ --- (Equation $1$)
Case $2$: After five years,Abhishek's age will be $(x+5)$ and Sweta's age will be $(y+5)$.
According to the problem: $(x+5) = 2(y+5)$
$x+5 = 2y+10$
$x-2y = 5$ --- (Equation $2$)
Thus,the required pair of linear equations is $x-4y = -9$ and $x-2y = 5$.