Obtain the value of the following polynomial at the given values of $x$: $p(x) = 10 - 5x + 3x^2 - x^3$; at $x = 2$ and $x = -2$.

The zero of the linear polynomial $p(x) = 3x - 6$ is $\ldots$

Divide : $3x^{2} - x^{3} - 3x + 5$ by $x - 1 - x^{2}$.

The product of two polynomials is $x^{3}-3x^{2}-x+3$ and one of the polynomials is $x+1$. Find the other polynomial.

Divide $x^{3}-6 x^{2}+11 x-6$ by $x^{2}+x+1$.

For each of the following,find a quadratic polynomial whose sum and product of the zeroes are as given respectively. Also,find the zeroes of these polynomials by factorisation.
Sum of zeroes $= -\frac{8}{3}$,Product of zeroes $= \frac{4}{3}$