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(C) Let $A$ be the event of drawing a queen and $B$ be the event of drawing a heart.Total number of cards = $52$.Number of queens $n(A) = 4$,so $P(A)

Vedclass · Accepted Answer

$\frac{4}{13}$

Vedclass · Answer

(C) Let $A$ be the event of drawing a queen and $B$ be the event of drawing a heart.Total number of cards = $52$.Number of queens $n(A) = 4$,so $P(A) = \frac{4}{52} = \frac{1}{13}$.Number of hearts $n(B) = 13$,so $P(B) = \frac{13}{52} = \frac{1}{4}$.The card that is both a queen and a heart is the queen of hearts,so $n(A \cap B) = 1$,which means $P(A \cap B) = \frac{1}{52}$.Using the addition theorem of probability,$P(A \cup B) = P(A) + P(B) - P(A \cap B)$.$P(A \cup B) = \frac{4}{52} + \frac{13}{52} - \frac{1}{52} = \frac{16}{52} = \frac{4}{13}$.

One card is drawn from a pack of $52$ cards. The probability that it is a queen or a heart is

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