One gram of hydrogen is found to combine with | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The equivalent weight of an element is defined as the mass of the element that combines with $1 \ g$ of hydrogen or $8 \ g$ of oxygen or $35.5 \ g

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(B) The equivalent weight of an element is defined as the mass of the element that combines with $1 \ g$ of hydrogen or $8 \ g$ of oxygen or $35.5 \ g$ of chlorine or its equivalent mass of bromine.Given that $1 \ g$ of hydrogen combines with $80 \ g$ of bromine,the equivalent weight of bromine is $80 \ g$.We are given that $4 \ g$ of bromine combines with $1 \ g$ of calcium.Since $80 \ g$ of bromine is the equivalent weight of bromine,the amount of calcium that combines with $80 \ g$ of bromine will be its equivalent weight.Equivalent weight of calcium $= \frac{1 \ g 	ext{ of } Ca}{4 \ g 	ext{ of } Br} 	imes 80 \ g 	ext{ of } Br = 20 \ g$.

One gram of hydrogen is found to combine with $80 \ g$ of bromine. One gram of calcium (valency $= 2$) combines with $4 \ g$ of bromine. The equivalent weight of calcium is:

Similar Questions

The mass of one mole of a substance in grams is called ....... .

Write formulas for the following compounds:
$(1)$ Iron $(III)$ sulphate
$(2)$ Chromium $(III)$ oxide

Calculate the mass of $100$ molecules of oxygen $(O_2)$ in $amu$ and in grams.

The equivalent mass of a divalent metal is $31.82$. What is the mass of a single atom of this metal?

In the chemical scale,the relative atomic mass of the naturally occurring isotopic mixture of oxygen atoms $({}^{16}O, {}^{17}O, {}^{18}O)$ is taken as:

Vedclass Test Series

Exam Paper Generator

Online Exam Module