One microgram of matter converted into energy will give:

$A$ nucleus $^{A}_{Z} X$ has mass represented by $M(A, Z)$. If $M_p$ and $M_n$ denote the mass of a proton and a neutron respectively, and $B.E.$ is the binding energy in $MeV$, then:

Nucleus $A$ has a mass number of $220$ and its binding energy per nucleon is $5.6 \, MeV$. It splits into two fragments '$B$' and '$C$' with mass numbers $105$ and $115$,respectively. The binding energy per nucleon for both '$B$' and '$C$' is $6.4 \, MeV$. The energy $Q$ released per fission will be............$MeV$.

State Einstein's special theory of relativity and provide the mass-energy equivalence formula.

The rest mass of the deuteron,${}_1^2H$,is equivalent to an energy of $1876 \, MeV$. The rest mass of a proton is equivalent to $939 \, MeV$ and that of a neutron is $940 \, MeV$. $A$ deuteron may disintegrate into a proton and a neutron if it:

The binding energy per nucleon versus mass number curve for nuclei is shown in the figure. $W, X, Y$ and $Z$ are four nuclei indicated on the curve. The process that would release energy is